二‧情報虛實位能差(泡沫)707Please respect copyright.PENANAYdOk36pGMV
707Please respect copyright.PENANAYypnwHNLQj
錯誤情報與真實情報,會在觀測者與被觀測物之間產生能量差,系統中的量子會從高處往低處流動,捕捉其運動軌跡就能推導未知事件。707Please respect copyright.PENANA25wOC687yv
707Please respect copyright.PENANAQNEPgk6sEP
例:707Please respect copyright.PENANAHvoJaCdpOp
封閉的箱子中有一顆蘋果,設總熵為1。707Please respect copyright.PENANAF7Dern3CVv
觀測者被告知情報:箱子中有一顆蘋果,總熵為1。707Please respect copyright.PENANAc9HvyBqtkE
開啟箱子,兩系統的總熵相等,因果收束前後沒有情報能量流動。707Please respect copyright.PENANA2OULFas95g
707Please respect copyright.PENANAIPdhP5OnFB
封閉的箱子中有一顆蘋果,設總熵為1。707Please respect copyright.PENANAQlPlxsIWON
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。707Please respect copyright.PENANASlM8HK4RSh
開啟箱子,兩系統的總熵差1,因果收束前後有情報能量流動。707Please respect copyright.PENANAbhL4TpMXHl
707Please respect copyright.PENANAJ6ShcRAPCJ
封閉的箱子中有一顆蘋果,設總熵為1。707Please respect copyright.PENANAGNfVn93ATX
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。707Please respect copyright.PENANAXTeROWJM3K
不開啟箱子,兩系統的總熵差1,此差異持續存在的狀態,專案內稱之為泡沫。707Please respect copyright.PENANAhKcH7wJLWR
707Please respect copyright.PENANAl6ZjSWw4dQ
封閉的箱子中有一顆蘋果,設總熵為1。707Please respect copyright.PENANAyqhwx5Y6y7
100名觀測者被告知情報:箱子中有兩顆蘋果,總熵為2*100=200。707Please respect copyright.PENANAVdtOho3Ht7
不開啟箱子,兩系統的總熵差199,此差異持續存在的狀態,總共有199顆泡沫。707Please respect copyright.PENANAJHMPBgznO0
707Please respect copyright.PENANA4Y7nDzaVSQ
根據第二定律,宇宙中的情報總熵必定趨向均衡。泡沫產生的混亂必定會分散至其他系統中。比如:多出來的那些「不存在的蘋果」導致價格下跌,果農賺得的能量因而減少。707Please respect copyright.PENANAeNnNeUQPa2
707Please respect copyright.PENANAM364odRSg2
定位、統計、歸納,得知所有粒子的運動狀態就能計算出未來的動向。觀察、分析、統整這些資訊,並導入演算機中的工作,本應交由AI電子腦擔任,但原初智叛亂後,現今局勢反對高性能AI生產,最合乎成本效益的解決方案就是人類頭腦。處理如此複雜的系統需要大量樣本,且必定會出現損壞,最好的方式就是使用Q型複製人。707Please respect copyright.PENANAXwdBnq3RpS
707Please respect copyright.PENANAb3mCIQw805
(New)707Please respect copyright.PENANA11NqLR8Vyl
新展望:加入纏結粒子技術的精準推導法,下述。707Please respect copyright.PENANA9in0o22elo
707Please respect copyright.PENANAlDIp4YHk66
arrow_back
拉普拉斯演算機:情報泡沫儲存槽
more_vert
-
info_outline Info
-
toc Table of Contents
-
share Share
-
format_color_text Display Settings
-
exposure_plus_1 Recommend
-
Sponsor
-
report_problem Report
-
account_circle Login
Search stories, writers or societies
Continue ReadingClear All
What Others Are ReadingRefresh
X
Never miss what's happening on Penana!
拉普拉斯演算機:情報泡沫儲存槽
Author:
LiCh 阿立
ISSUE #2
預知未來的方法:因果率演算理論模型(二)
LIKES 0
READS 703
BOOKMARKS 3
campaign
Request update 0
Sponsor
Suggest Edits
Login with Facebook
or Sign up/Login to comment or bookmark! Click to load the next chapter
x
will be deducted
will be deducted Your current coin balance: 0Click to buy coins
A recurring charge will be deducted , unless you decide to cancel. You can cancel your subscription at any time.
You can also pay with credit card
X
After each update request, the author will receive a notification!
smartphone100
→ Request update
X
Sponsor again
Click to login
Login first to show your name as a sponsor.
Thank you for supporting the story! :)
Please Login first.
×
Write down what you like about the story
×
Reading Theme:
Font Size:
Line Spacing:
Paragraph Spacing:
Load the next issue automatically
Reset to default
×
People Who Like This
x
Before You Publish
Please ensure your story does not contain illegal, hateful, inciting, or violence-promoting content, or any infringing, plagiarized, or spam material, and that it complies with Penana’s Terms of Use.
Penana reserves the right to remove any content that violates these rules or causes legal or community risk, and to suspend or terminate related accounts.
