科普專欄–薯不揀單 - 深入淺出–點解瘦削運動員都能夠跑畢馬拉松全程？

在長時間的運動下，脂肪會為身體帶來能源，支撐身體肌肉所需。馬拉松全程為42.195km，脂肪所提供的能源協助絕對不可或缺。1005Please respect copyright.ＰＥＮＡＮＡG0q7Iq47dm
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在這個前題下，為何為數不少的瘦削運動員都可以足夠應付長距離的馬拉松呢?1005Please respect copyright.ＰＥＮＡＮＡQv8Pt5aebT
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（圖2）在此，我們嘗試一下利用數學角度，以卡路里的消耗量探討這一個問題。1005Please respect copyright.ＰＥＮＡＮＡn3G7jzUzpD
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有研究確認(Ref1,2)，身體消耗的卡路里是與行走總距離有關，而非行走速度。1005Please respect copyright.ＰＥＮＡＮＡlpfp94z6V0
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他們最終得出的公式為每1kg行走1km平地就會消耗1卡路里。1005Please respect copyright.ＰＥＮＡＮＡlywTk79AtG
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如果我們假設1個70kg的男人跑一場馬拉松，所消耗的總卡路里就會為1005Please respect copyright.ＰＥＮＡＮＡO1ZDiUPywL
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70kg x 42.195km=1005Please respect copyright.ＰＥＮＡＮＡ0hS8QRyJUC
2950kcal1005Please respect copyright.ＰＥＮＡＮＡ0QpyA18dfa
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（圖3）身體的脂肪每克約可以提供9kcal，如果我們用上最極端的例子，負責儲存能源的體脂只佔身體重量2% (正常為10-32%)的話，所提供得到的能源就會是1005Please respect copyright.ＰＥＮＡＮＡWW7nlvq4Gm
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70kg x 1000 x 2% x 91005Please respect copyright.ＰＥＮＡＮＡVOeSFQfYLV
=12600 kcal1005Please respect copyright.ＰＥＮＡＮＡ4HUcGakWP2
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而基於每場馬拉松所消耗的卡路里僅為2950kcal關係，12600/2950 = 4.27，單憑身體脂肪所提供的能源，就足以應付4場馬拉松!1005Please respect copyright.ＰＥＮＡＮＡo09qWu9nIy
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這個跑4次馬拉松的結果是以極低（儲存能量用的體脂2%）這個極端例子作計算，可以推算得到正常人的話絕對是遊刃有餘跑1場馬拉松；1005Please respect copyright.ＰＥＮＡＮＡae5xwH0SQP
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此計算方式是假設整場馬拉松是平地鋪設，沒有高低鈄坡。1005Please respect copyright.ＰＥＮＡＮＡarLz0uLFhQ
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（圖4）不過，魔鬼在細節，這集反應熱烈的話，下一集將會探討這個計算方式的漏洞以及馬拉松選手經常會遇到所謂Hit The Wall的問題。1005Please respect copyright.ＰＥＮＡＮＡx9aPFRY9Je
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如果想我快啲出文的話，請入去Penana網站科普專欄–薯不揀單俾一個like以及Bookmark，這對我非常之重要。1005Please respect copyright.ＰＥＮＡＮＡykWhQjJHCF
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Link: https://www.penana.com/story/66244/%E7%A7%91%E6%99%AE%E5%B0%88%E6%AC%84-%E8%96%AF%E4%B8%8D%E6%8F%80%E5%96%AE/toc1005Please respect copyright.ＰＥＮＡＮＡYyCk4M3aR5
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同時亦可以在Penana網站裡按「買一嚿/半嚿薯仔」，以課金的方式推動我繼續搜羅資料寫文，多謝。1005Please respect copyright.ＰＥＮＡＮＡw4kRVaa2vT
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Link:1005Please respect copyright.ＰＥＮＡＮＡqLUaj9YD6V
https://www.penana.com/user/27349/%E8%96%AF%E4%BB%94%E8%81%9E%E8%8C%B1%E8%8E%89/portfolio1005Please respect copyright.ＰＥＮＡＮＡs45jyVYbpb
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有興趣接收科學資訊的話，歡迎follow IG: potatopigtongue。1005Please respect copyright.ＰＥＮＡＮＡnBQ2j5HeNa
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Ref1:https://journals.physiology.org/doi/abs/10.1152/jappl.1963.18.2.3671005Please respect copyright.ＰＥＮＡＮＡ30zI4wCWiy
Ref2:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1859586/1005Please respect copyright.ＰＥＮＡＮＡB3UerWhlza