Given a string s, reverse only all the vowels in the string and return it.
The vowels are 'a', 'e', 'i', 'o', and 'u', and they can appear in both lower and upper cases, more than once.
348Please respect copyright.ＰＥＮＡＮＡcfKVbu8KFV
Two Pointers
class Solution {348Please respect copyright.ＰＥＮＡＮＡQHmE9bVdV1
// Return true if the character is a vowel (case-insensitive)348Please respect copyright.ＰＥＮＡＮＡG7ekG7oy1L
// booleann(for ture or false), 創造"isVowel"(class), 命名(char c), and add aeiouAEIOU348Please respect copyright.ＰＥＮＡＮＡh3JgeCSz2I
// 當 (char c) 不是vowel，return false/ 是vowel，return true
// * a||b = ab 全为 false 时，计算结果为 false，否则为 true。348Please respect copyright.ＰＥＮＡＮＡcd502xXM3W
boolean isVowel(char c) {348Please respect copyright.ＰＥＮＡＮＡqRYSQtjLtm
return c == 'a' || c == 'i' || c == 'e' || c == 'o' || c == 'u'348Please respect copyright.ＰＥＮＡＮＡvBhYppaKdY
|| c == 'A' || c == 'I' || c == 'E' || c == 'O' || c == 'U';348Please respect copyright.ＰＥＮＡＮＡtZSQCTGgwE
}348Please respect copyright.ＰＥＮＡＮＡlTHpkbEZmr
348Please respect copyright.ＰＥＮＡＮＡhTGdZWXeeB
// Function to swap characters at index x and y348Please respect copyright.ＰＥＮＡＮＡaptTH2DoEW
void swap(char[] chars, int x, int y) {348Please respect copyright.ＰＥＮＡＮＡOnDheeQ3AR
char temp = chars[x];348Please respect copyright.ＰＥＮＡＮＡuOCZEFTCTi
chars[x] = chars[y];348Please respect copyright.ＰＥＮＡＮＡfY2HpnnwFK
chars[y] = temp;348Please respect copyright.ＰＥＮＡＮＡEir9pyx9hI
}348Please respect copyright.ＰＥＮＡＮＡgup6fZV038
348Please respect copyright.ＰＥＮＡＮＡzbfVh4cVvk
public String reverseVowels(String s) {348Please respect copyright.ＰＥＮＡＮＡQIXZzCS5OG
// 設定最左的字母是[0]348Please respect copyright.ＰＥＮＡＮＡZ5DRNERPXY
int start = 0;348Please respect copyright.ＰＥＮＡＮＡVBqQO8xIQX
// 設定最右的字母是[文字總長度-1].348Please respect copyright.ＰＥＮＡＮＡZIlC51dx4q
int end = s.length() - 1;348Please respect copyright.ＰＥＮＡＮＡ60jIULg2se
// 將 String 轉換為 char 數組，因為 String 在 Java 中是不可變的348Please respect copyright.ＰＥＮＡＮＡzg2TMv25OQ
char[] sChar = s.toCharArray();348Please respect copyright.ＰＥＮＡＮＡojOtQ6dUPO
348Please respect copyright.ＰＥＮＡＮＡZdnVNxec4U
// While we still have characters to traverse348Please respect copyright.ＰＥＮＡＮＡyRGepNzpEu
// while the word more than one letter, do this function348Please respect copyright.ＰＥＮＡＮＡt4o0n2CnPi
while (start < end) {348Please respect copyright.ＰＥＮＡＮＡFmFrpFWQYe
// Find the leftmost vowel348Please respect copyright.ＰＥＮＡＮＡfGg5CPEzsH
// while start 少於 string length() 同時 [start] 不是vowel，return start ++348Please respect copyright.ＰＥＮＡＮＡdX9BZPxITA
while (start < s.length () && !isVowel(sChar[start])) {348Please respect copyright.ＰＥＮＡＮＡ2c5h0eO1LU
start++;348Please respect copyright.ＰＥＮＡＮＡre2NnJ2rdb
}348Please respect copyright.ＰＥＮＡＮＡ0LjYDatugB
// Find the rightmost vowel348Please respect copyright.ＰＥＮＡＮＡ4Fl3ETaikY
// while end 大於 0 同時 [end] 不是vowel，return end --348Please respect copyright.ＰＥＮＡＮＡNPaDl5ndSm
while (end >= 0 && !isVowel(sChar[end])) {348Please respect copyright.ＰＥＮＡＮＡ7W8EollKJc
end--;348Please respect copyright.ＰＥＮＡＮＡ1YOQQ40rOM
}348Please respect copyright.ＰＥＮＡＮＡkpsd7sRwCe
// Swap them if start is left of end348Please respect copyright.ＰＥＮＡＮＡsvRLVPrQPg
// swap function: (in what string, value 1, value 2), swap value 1 and 2348Please respect copyright.ＰＥＮＡＮＡymtfEiNuo4
if (start < end) {348Please respect copyright.ＰＥＮＡＮＡiFwsDUjF2J
swap(sChar, start++, end--);348Please respect copyright.ＰＥＮＡＮＡsuzFJ7jOsJ
}348Please respect copyright.ＰＥＮＡＮＡDEMWYucevq
}348Please respect copyright.ＰＥＮＡＮＡMk5yPtrXVS
348Please respect copyright.ＰＥＮＡＮＡwOzLtrrvrO
// Converting char array back to String348Please respect copyright.ＰＥＮＡＮＡnA6qdAKHfp
// 顯示新的String348Please respect copyright.ＰＥＮＡＮＡSGnttJy1OX
return new String(sChar);348Please respect copyright.ＰＥＮＡＮＡYu2oMAUo3C
}348Please respect copyright.ＰＥＮＡＮＡgsNyWwN1kR
};
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