Given a string s, reverse only all the vowels in the string and return it.
The vowels are 'a', 'e', 'i', 'o', and 'u', and they can appear in both lower and upper cases, more than once.
333Please respect copyright.ＰＥＮＡＮＡOXNxApuvOQ
Two Pointers
class Solution {333Please respect copyright.ＰＥＮＡＮＡUs3Zs67osG
// Return true if the character is a vowel (case-insensitive)333Please respect copyright.ＰＥＮＡＮＡuDEDWbjJBF
// booleann(for ture or false), 創造"isVowel"(class), 命名(char c), and add aeiouAEIOU333Please respect copyright.ＰＥＮＡＮＡAIu0OzyGqb
// 當 (char c) 不是vowel，return false/ 是vowel，return true
// * a||b = ab 全为 false 时，计算结果为 false，否则为 true。333Please respect copyright.ＰＥＮＡＮＡSFB03itUWi
boolean isVowel(char c) {333Please respect copyright.ＰＥＮＡＮＡJYcv9i4AQY
return c == 'a' || c == 'i' || c == 'e' || c == 'o' || c == 'u'333Please respect copyright.ＰＥＮＡＮＡXOaCqIiUGf
|| c == 'A' || c == 'I' || c == 'E' || c == 'O' || c == 'U';333Please respect copyright.ＰＥＮＡＮＡAylKON3fCQ
}333Please respect copyright.ＰＥＮＡＮＡhyfJiKk0H4
333Please respect copyright.ＰＥＮＡＮＡyL2XPC2D5s
// Function to swap characters at index x and y333Please respect copyright.ＰＥＮＡＮＡ9zBVCJn7dF
void swap(char[] chars, int x, int y) {333Please respect copyright.ＰＥＮＡＮＡsaeNVnXgMw
char temp = chars[x];333Please respect copyright.ＰＥＮＡＮＡbJlaqS2e9d
chars[x] = chars[y];333Please respect copyright.ＰＥＮＡＮＡf6mQiIpwjV
chars[y] = temp;333Please respect copyright.ＰＥＮＡＮＡXW11MozXji
}333Please respect copyright.ＰＥＮＡＮＡiFiI9keONW
333Please respect copyright.ＰＥＮＡＮＡ8uPFd0V1Wb
public String reverseVowels(String s) {333Please respect copyright.ＰＥＮＡＮＡxyllyl4DLa
// 設定最左的字母是[0]333Please respect copyright.ＰＥＮＡＮＡRJ91gXDKYn
int start = 0;333Please respect copyright.ＰＥＮＡＮＡ1qOLTVJ0WW
// 設定最右的字母是[文字總長度-1].333Please respect copyright.ＰＥＮＡＮＡG9uOvcIvYp
int end = s.length() - 1;333Please respect copyright.ＰＥＮＡＮＡp0HggqIA8o
// 將 String 轉換為 char 數組，因為 String 在 Java 中是不可變的333Please respect copyright.ＰＥＮＡＮＡbWxBg06AxK
char[] sChar = s.toCharArray();333Please respect copyright.ＰＥＮＡＮＡAnPMu4Najz
333Please respect copyright.ＰＥＮＡＮＡ1aGoJkU5yr
// While we still have characters to traverse333Please respect copyright.ＰＥＮＡＮＡQZQRMrqkjj
// while the word more than one letter, do this function333Please respect copyright.ＰＥＮＡＮＡHsrodZyq2E
while (start < end) {333Please respect copyright.ＰＥＮＡＮＡT9SNNwdePm
// Find the leftmost vowel333Please respect copyright.ＰＥＮＡＮＡuth5KDufSg
// while start 少於 string length() 同時 [start] 不是vowel，return start ++333Please respect copyright.ＰＥＮＡＮＡsTfERezASW
while (start < s.length () && !isVowel(sChar[start])) {333Please respect copyright.ＰＥＮＡＮＡu3sCXiqWNw
start++;333Please respect copyright.ＰＥＮＡＮＡ0jPAJTTytN
}333Please respect copyright.ＰＥＮＡＮＡCK0UXM7UzS
// Find the rightmost vowel333Please respect copyright.ＰＥＮＡＮＡ89ldxppZ8r
// while end 大於 0 同時 [end] 不是vowel，return end --333Please respect copyright.ＰＥＮＡＮＡemwsO4TsFC
while (end >= 0 && !isVowel(sChar[end])) {333Please respect copyright.ＰＥＮＡＮＡtgWWQR6zLf
end--;333Please respect copyright.ＰＥＮＡＮＡYjYP6Gi0Mh
}333Please respect copyright.ＰＥＮＡＮＡhB2iiWHL8O
// Swap them if start is left of end333Please respect copyright.ＰＥＮＡＮＡXdbDPzJ72v
// swap function: (in what string, value 1, value 2), swap value 1 and 2333Please respect copyright.ＰＥＮＡＮＡWqz4nFNTYZ
if (start < end) {333Please respect copyright.ＰＥＮＡＮＡ7wKWu69n9F
swap(sChar, start++, end--);333Please respect copyright.ＰＥＮＡＮＡUsUQouFADV
}333Please respect copyright.ＰＥＮＡＮＡMUJA7koFbx
}333Please respect copyright.ＰＥＮＡＮＡlUQkODKNhr
333Please respect copyright.ＰＥＮＡＮＡ0aJ8Re89t8
// Converting char array back to String333Please respect copyright.ＰＥＮＡＮＡsoOtcvbHEi
// 顯示新的String333Please respect copyright.ＰＥＮＡＮＡ7Yi60EzYll
return new String(sChar);333Please respect copyright.ＰＥＮＡＮＡRQrlwFN5ME
}333Please respect copyright.ＰＥＮＡＮＡuqKM1bt4G4
};
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