科普專欄–薯不揀單 - 深入淺出–點解瘦削運動員都能夠跑畢馬拉松全程？

在長時間的運動下，脂肪會為身體帶來能源，支撐身體肌肉所需。馬拉松全程為42.195km，脂肪所提供的能源協助絕對不可或缺。993Please respect copyright.ＰＥＮＡＮＡM4lPRhMPCx
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在這個前題下，為何為數不少的瘦削運動員都可以足夠應付長距離的馬拉松呢?993Please respect copyright.ＰＥＮＡＮＡ32DKrYuOqq
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（圖2）在此，我們嘗試一下利用數學角度，以卡路里的消耗量探討這一個問題。993Please respect copyright.ＰＥＮＡＮＡIcTKCHtOUw
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有研究確認(Ref1,2)，身體消耗的卡路里是與行走總距離有關，而非行走速度。993Please respect copyright.ＰＥＮＡＮＡvpd0GzVmjI
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他們最終得出的公式為每1kg行走1km平地就會消耗1卡路里。993Please respect copyright.ＰＥＮＡＮＡ5e1PUa6Vvt
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如果我們假設1個70kg的男人跑一場馬拉松，所消耗的總卡路里就會為993Please respect copyright.ＰＥＮＡＮＡQ2tU5N8q2P
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70kg x 42.195km=993Please respect copyright.ＰＥＮＡＮＡ6hiNW8EeZW
2950kcal993Please respect copyright.ＰＥＮＡＮＡEbjict6UBj
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（圖3）身體的脂肪每克約可以提供9kcal，如果我們用上最極端的例子，負責儲存能源的體脂只佔身體重量2% (正常為10-32%)的話，所提供得到的能源就會是993Please respect copyright.ＰＥＮＡＮＡPov9bSmlzC
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70kg x 1000 x 2% x 9993Please respect copyright.ＰＥＮＡＮＡ9hI2aP8o0T
=12600 kcal993Please respect copyright.ＰＥＮＡＮＡOAZ9JzaLSy
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而基於每場馬拉松所消耗的卡路里僅為2950kcal關係，12600/2950 = 4.27，單憑身體脂肪所提供的能源，就足以應付4場馬拉松!993Please respect copyright.ＰＥＮＡＮＡVubEo14vNe
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這個跑4次馬拉松的結果是以極低（儲存能量用的體脂2%）這個極端例子作計算，可以推算得到正常人的話絕對是遊刃有餘跑1場馬拉松；993Please respect copyright.ＰＥＮＡＮＡpvoqeMRgK8
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此計算方式是假設整場馬拉松是平地鋪設，沒有高低鈄坡。993Please respect copyright.ＰＥＮＡＮＡDEnPEc0MeH
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（圖4）不過，魔鬼在細節，這集反應熱烈的話，下一集將會探討這個計算方式的漏洞以及馬拉松選手經常會遇到所謂Hit The Wall的問題。993Please respect copyright.ＰＥＮＡＮＡHuFSTuszRj
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如果想我快啲出文的話，請入去Penana網站科普專欄–薯不揀單俾一個like以及Bookmark，這對我非常之重要。993Please respect copyright.ＰＥＮＡＮＡrFyQ6y5sGG
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Link: https://www.penana.com/story/66244/%E7%A7%91%E6%99%AE%E5%B0%88%E6%AC%84-%E8%96%AF%E4%B8%8D%E6%8F%80%E5%96%AE/toc993Please respect copyright.ＰＥＮＡＮＡKbcABvD53Z
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同時亦可以在Penana網站裡按「買一嚿/半嚿薯仔」，以課金的方式推動我繼續搜羅資料寫文，多謝。993Please respect copyright.ＰＥＮＡＮＡHABWYaSdhT
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https://www.penana.com/user/27349/%E8%96%AF%E4%BB%94%E8%81%9E%E8%8C%B1%E8%8E%89/portfolio993Please respect copyright.ＰＥＮＡＮＡbKFZekf0vA
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有興趣接收科學資訊的話，歡迎follow IG: potatopigtongue。993Please respect copyright.ＰＥＮＡＮＡyyDgmILAAg
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Ref1:https://journals.physiology.org/doi/abs/10.1152/jappl.1963.18.2.367993Please respect copyright.ＰＥＮＡＮＡn8oq1Ap0gN
Ref2:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1859586/993Please respect copyright.ＰＥＮＡＮＡGxF5Clb1y9